1/2+1/4+1/8+1/16+1/32+1/64+1/128+1/256
更新时间:2026-09-30 13:02:30
问题描述:
1/2+1/4+1/8+1/16+1/32+1/64+1/128+1/256
李廷友回答:
令m=1/2+1/4+1/8+1/16+1/32+1/64+1/128+1/256 两边同时乘2,得: 2m=1+1/2+1/4+1/8+...+1/128 两式相减,得: m=1-1/256=255/256 1/2+1/4+1/8+1/16+1/32+1/64+1/128+1/256 =(1-1/2)+(1/2-1/4)+(1/4-1/8)+...+(1/128-1/256) =1-1/2+1/2-1/4+1/4-1/8+...+1/128-1/256 =1-1/256 =255/256
